# 超声外科手术系统输出声功率的测量方法研究Measurement of Acoustic Output Poweron Ultrasonic-Surgical Systems

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This paper reviews the principle, method, importance and necessity of testing the output power of ultrasonic surgical system, and uses the hydrophone method to measure the output sound power of the ultrasonic hemostatic knife system. The experimental data are analyzed and discussed. The measurement method and experimental results are of great significance to evaluate the safety and efficacy of ultrasound surgical system.

1. 概述

2. 测量方法

2.1. 测量原理

2.2. 测量实验

Figure 1. AIMS III acoustic intensity measurement system

Figure 2. RHSA-10 hydrophone

${P}_{ad}=\frac{2\text{π}{r}^{2}|p{\left(r\right)}^{2}|}{\rho c}$ (1)

$p\left(r\right)=\frac{V}{{M}_{L}}$ (2)

${P}_{ad}=\frac{2\text{π}{r}^{2}{V}^{2}}{\rho c{M}_{L}^{2}}$ (3)

Figure 3. Test configuration

${P}_{ad}=\frac{4\text{π}{r}^{2}Vrm{s}^{2}}{\rho c{M}_{L}^{2}}$ (4)

${P}_{ad}=\frac{\text{π}{r}^{2}|p{\left(r\right)}^{2}|}{2\rho c}$ (5)

${P}_{ad}=\frac{\text{π}{r}^{2}{V}^{2}}{2\rho c{M}_{L}^{2}}$ (6)

3. 实验结果与讨论

3.1. 实验数据

Figure 4. Transmitted waveform

Figure 5. Waveform integral

1) 40 k的超声吸引刀具

ρ = 1000 kg/m3, c = 1500 m/s, r = 3.1 cm = 0.031 m,

VRMS = 0.997 V, ML = 2.0892 × 10−5 V/Pa, 根据标准要求，则有：

${P}_{ad}=\frac{4\text{π}{r}^{2}Vrm{s}^{2}}{\rho c{M}_{L}^{2}}=\frac{4×\text{π}×{0.031}^{2}×{\left(0.997\right)}^{2}}{1000×1.5×{10}^{3}×{\left(2.0892×{10}^{-5}\right)}^{2}}=17.16\text{\hspace{0.17em}}\text{W}$

2) 55 k的超声止血刀具

ρ = 1000 kg/m3, c = 1500 m/s, r = 3.0 cm = 0.030 m,

VRMS = 0.997 V, ML = 1.9275 × 10−5 V/Pa, 根据标准要求，则有：

${P}_{ad}=\frac{4\text{π}{r}^{2}Vrm{s}^{2}}{\rho c{M}_{L}^{2}}=\frac{4×\text{π}×{0.030}^{2}×{\left(0.418\right)}^{2}}{1000×1.5×{10}^{3}×{\left(1.9275×{10}^{-5}\right)}^{2}}=3.78\text{\hspace{0.17em}}\text{W}$

3) 40 K超声切骨刀具

ρ = 1000 kg/m3, c = 1500 m/s, r = 3.2 cm = 0.032 m,

VRMS = 0.893 V, ML = 2.0892 × 10−5 V/Pa, 根据标准要求，则有：

${P}_{ad}=\frac{4\text{π}{r}^{2}Vrm{s}^{2}}{\rho c{M}_{L}^{2}}=\frac{4×\text{π}×{0.032}^{2}×{\left(0.893\right)}^{2}}{1000×1.5×{10}^{3}×{\left(2.0892×{10}^{-5}\right)}^{2}}=15.66\text{\hspace{0.17em}}\text{W}$

Table 1. Measurement summary

3.2. 结果汇总

3.3. 结果讨论

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